112x^2+37x=0

Solution for 112x^2+37x=0 equation:

112x^2+37x=0

a = 112; b = 37; c = 0;
Δ = b2-4ac
Δ = 372-4·112·0
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-37}{2*112}=\frac{-74}{224}
=-37/112
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+37}{2*112}=\frac{0}{224}
=0
$